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BMC 10 - Novy Liskovec Traditional Cache

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abakus: viz http://www.geocaching.cz/forum/viewthread.php?forum_id=4&thread_id=9288&pid=102628#post_102628

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Hidden : 8/12/2007
Difficulty:
1 out of 5
Terrain:
1.5 out of 5

Size: Size:   micro (micro)

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Geocache Description:


Brnenske mestske casti: Novy Liskovec

Zakladni informace

Katastralni uzemi: Novy Liskovec
Pocet obyvatel: 11.338
Podil z Brna: 2,9 %
Oficialni stranky mestske casti

Nejstarsi geocache: GCWAW4 Cest jejich pamatce No. 1
Geocacheri: (zadny s 300+ nalezy)

Misto ulozeni:

Keska

O serii

K teto geocacherske serii jsem se nechal castecne inspirovat v New Jersey. O co jde?
V kazde brnenske mestske casti bude umistena geocache. Budou to vse mikrousi, snadno nalezitelns, v neprilis exponovanych mistech. Cilem totiz neni testovat, co vsechno jste schopni a ochotni vydrzet, ale povodit vas po Brne. Mozna se najdou i kesky "s vyzvou" a kdyz uz tady vznikne takova serie, tak by se slusela i bonusovka.

Brno ma celkem 29 mestskych casti, ktere obsahuji 48 katastralnich uzemi (stav v cervenci 2007). Nas bude zajimat pouze cleneni na mestske casti, z cehoz plyne, ze bude celkem 29 geocachi + 1 bonusovka.

Dalsi informace o cleneni Brna naleznete na nasledujicich www strankach:

Wikipedie
Encyklopedie dejin mesta Brna
Uzemni plan

Aktualni informace o serii BMC najdete ZDE.

POZOR: V krabicce najdete ctyrmistne magicke císlo, ktere se vam jednou bude hodit ;o)

English

Brno districts series: Brno-stred

There are – or will be – geocaches in each of twenty-nine Brno districts. The caches are very simple with goal to take you around Brno city.
You will find special magic number in each of the geocaches which is necessary for solving te bonus cache. Unfortunately it will not be possible to solve the puzzle without knowledge of the Czech language so you don't have to care about the number.

Additional Hints (Decrypt)

Ynivpxn ceb yrinxl / Orapu sbe yrsg-unaqrq

Decryption Key

A|B|C|D|E|F|G|H|I|J|K|L|M
-------------------------
N|O|P|Q|R|S|T|U|V|W|X|Y|Z

(letter above equals below, and vice versa)